|
Aleister Crowley Diary Entry Saturday, 29 September 1923
Die Saturn
Hail unto Kheph Ra!
1.11 a.m. Give symbol for following advice given in Eddie's [Eddy Saayman] vision of yesterday afternoon.
[I Ching Hexagram] LII Kăn [Earth/Earth]
Couldn’t be better: corresponds perfectly with advice.
(I get an impression of Pontoise—which I love well of old)
785 [is] a name of
500 = ϕ = Geburah = σπ = 6.
οι σε c. f. oisif French, lazy!
ο'ις sheep ο'ισου rope—c.f. oisier
= Expectation of
Amiens = friendly Abbeville = Father—town.
Calais = beautiful. Creil no good.
Dunkirk = no good.
St. Germaine!! en Laye!!!
(Shall I ‘become’ Comte de St. Germain with a wig & beard—and start a New Legend?)
St. Germaine en Laye
871 = χαος = βαβαλου = 13 x 67 the Womb containing the Twins.
Hilly-wooded.
4.00 a.m. Last night at Palmarium I began to work on a Heptopsis Theorem which I think may be developed into a gen[era]l Factorial Theorem.
7n + 1 7n + 2 3 4 5 6 7 10 = 7 x 1 + 3 100 = 7 x 14 + 2 1000 = 7 x 142 + 6 100,000 = 7 x 1428 + 4 = 7 x 1420 + 60 = (7 x 8) + 4 1-6 [zeroes =] 7 x 14285 + 5 1-7 [zeroes =]7 x 142857 + 1 1-8 [zeroes =] 7 x 1428571 + 3 1-9 [zeroes =] 7 x 14285714 + 2, etc. recurs.
(There is something profound in this recurrence of digits & remainders, & the symmetry of the table opposite [i.e. above])
Next steps to chop no. into series of 7 ? 6 digits & to correlate order of new figures with no. of columns.
To determine the remainder q in p—q = 7n.
[Calculations omitted.]
Add digits of new number: repeat process if necessary: divide by 7: remainder is that of original number. Similar tables to be constructed for each prime.
Millions are—Tens. 10 " —Hundreds &c. &c. 100 " ∴ The unit digit—the Thousand digit = the new Thousand digit
e.g. for 7 < 8003 write 7 < 50000 1147 + 2 714 + 2
New rule appears:
Cancel the unit digit, subtract it from the Thousand digit (adding if necessary) & so far the 10 digit & 10 Thou[sand) digit &c. &c. Thus
P.S: ➗ 7 = 4584946 9310 + 3
? add significant digits (subtracting when sum > 7). Thus 151 + 112 = 263 & treat result as if the only no.
But subtract 263 - 1 = 262 = 37 + 3.
Any multiple of 7 which strikes the eye may be removed from these new numbers, or from original no. or remainder written (thus 112 = √0 and 296 = 16 = 2).
Eg. 2 6 4 9 9 8 7 2 1 6 3 8 5 5 6 2 7 9 1 4 √ 5 0 0 2 0 3 0 0 0 0 1 5 0 0 2 0 0 0 4 √ 3 : 0 0 0 0 3 0 : 0 0 0 1 3 0 : 0 1 0 0 0 4
Next, remove multiples of 1001 (√2).
Next, shift remainders to unit col[umn] of each sec[tio]n.
(Adding remainders of difficult digits by table-thus 0100004: the 1 in col[umn] 5 has rem[ainder] 4.)
√3 3:000002:000004:000001 √4 Add sight[?] digits: rem[ainder] = rem[ainder] of ones [?]. √4 3 + 2 + 4 + 1 = 10 = 7 + 3.
P.S. = 7n + 3.)
To apply this method to 13.
α. Construct table
&c till it recurs (if necessary?) (see א [below]).
Combining the methods of table, remainder square, inspection, reduction, & chopping, one should have remainder of a 1050 no. in 10 minutes. And so ad libitum.
[Section:] [Aleph]
√2 Next remove remainders, using tables, to right hand of bar.
[Experimental and confused calculations omitted here.]
New principle. Treat each million set by itself: hence table need only cover 1st million. Only: remainder must go to col[umn] on right.
Make table of no. x 1 . . . 9 for convenience of cancelling.
— — — 11 — — — 4 — — — 15
286 290
11 — — — 15 286 291
12
q = 12
Try a perfect bugger 1301
10,000 9,107 893
P.S. No—I’m too weak at present.
1.36 p.m. CCXX, III.47 him not seek &c, may refer to child, not to 666: ‘after this’? what ‘this’? also, what ‘It’ & ‘his’ in previous sentence?
III.45 I wonder if this means L[iber] Z. 43, 44 describe Rose’s conduct & fate.
|
.
[Water] i.e. pleasure repose.
